## Editorial for A Plus B

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Submitting an official solution before solving the problem yourself is a bannable offence.

Author: moncef

Read $$N$$

Repeat for each $$i$$ from $$1$$ to $$N$$

• Read $$a$$
• Read $$b$$
• output $$a+b$$

End

#### Assembly Solution

#features: libc

.data
str:
.string "%d"

str2:
.string "%d %d"

str3:
.string "%d\n"

.text

.globl main
main:
pushq %rbp
movq %rsp, %rbp
subq $16, %rsp movq$str, %rdi
leaq -4(%rbp), %rsi

call scanf

loop:
movq $str2, %rdi leaq -8(%rbp), %rsi leaq -12(%rbp), %rdx call scanf movl -8(%rbp), %eax addl -12(%rbp), %eax movq$str3, %rdi
movl %eax, %esi

call printf

decl -4(%rbp)
cmpl $0, -4(%rbp) jne loop movq$0, %rax

leave

ret

#### Python Solution

N = int(input())

for _ in range(N):
a, b = map(int, input().split())
print(a + b)

#### Java Solution

import java.util.*;

public class APlusB {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);

int N = in.nextInt();
for (int i = 0; i < N; i++) {
int a = in.nextInt();
int b = in.nextInt();
System.out.println(a + b);
}
}
}

#### JavaScript Solution

let args = gets();
for (let i = 0; i < args; i++) {
let numbers = gets().split(' ');
print(parseInt(numbers[0]) + parseInt(numbers[1]));
}

#### PHP Solution

<?php
$n = rtrim(fgets(STDIN));$result = [];
for ($i=0;$i < $n;$i++){
$add = rtrim(fgets(STDIN));$result[] += array_sum(explode(" ", $add)); } for($i=0; $i < count($result); $i++){ echo "$result[$i] \n"; } ?> #### C# Solution using System; namespace aplusb { class Program { static void Main(string[] args) { var count = int.Parse(Console.ReadLine()); for(var x = 0; x < count; x++) { var parts = Console.ReadLine().Split(' '); System.Console.WriteLine(int.Parse(parts[0]) + int.Parse(parts[1])); } } } } #### C++ Solution #include <iostream> using namespace std; int main() { int N; cin >> N; for (int i = 0; i < N; i++) { int a, b; cin >> a >> b; cout << a + b << endl; } } #### Perl Solution chomp($n = <>);
for ($i = 0;$i<$n;$i = $i +1) { chomp($line = <>);
($a,$b)= split / +/, $line;$c = $a +$b;
print "\$c\n";
}

#### Ruby Solution

n = gets.to_i
n.times {
a, b = *gets.split.map{|x|x.to_i}
puts a+b
}