## Road Closures

### Road Closures

In the city of Surabaya, there are \(N\) junctions, numbered from \(0\) to \(N - 1\). These junctions are connected by \(N - 1\) bidirectional roads, numbered from \(0\) to \(N - 2\), such that there is a unique path between any pair of junctions through the roads. Road \(i\) (\(0 \le i \le N - 2\)) connects junction \(U[i]\) and \(V[i]\).

To raise environmental awareness, Pak Dengklek, as the mayor of Surabaya, plans to hold a Car Free Day.
To encourage the event, Pak Dengklek will organize road closures.
Pak Dengklek will first choose a non-negative integer \(k\), then close some of the roads such that each junction is directly connected to **at most** \(k\) roads that are not closed.
The cost to close road \(i\) is \(W[i]\).

Help Pak Dengklek to find the minimum total cost to close the roads for each possible non-negative integer \(k\) (\(0 \le k \le N - 1\)).

#### Implementation Details

You should implement the following procedure:

`int64[] minimum_closure_costs(int N, int[] U, int[] V, int[] W)`

- \(N\): the number of junctions in Surabaya.
- \(U\) and \(V\): arrays of size \(N - 1\), where junctions \(U[i]\) and \(V[i]\) are connected by road \(i\).
- \(W\): an array of size \(N - 1\), where \(W[i]\) is the cost to close road \(i\).
- This procedure should return a single array of size \(N\). For each \(k\) (\(0 \le k \le N - 1\)), the \(k\)-th element is the minimum total cost to close the roads such that each junction is directly connected to at most \(k\) roads that are not closed.
- This procedure is called exactly once.

#### Examples

##### Example 1

Consider the following call:

`minimum_closure_costs(5, [0, 0, 0, 2], [1, 2, 3, 4], [1, 4, 3, 2])`

This means there is a total of \(5\) junctions and \(4\) roads connecting the junction pairs \((0, 1)\), \((0, 2)\), \((0, 3)\), and \((2, 4)\) with closure costs \(1\), \(4\), \(3\), and \(2\), respectively.

To obtain the minimum costs:

- if Pak Dengklek chose \(k = 0\), then all roads should be closed with a total cost of \(1 + 4 + 3 + 2 = 10\);
- if Pak Dengklek chose \(k = 1\), then road \(0\) and road \(1\) should be closed with a total cost of \(1 + 4 = 5\);
- if Pak Dengklek chose \(k = 2\), then road \(0\) should be closed with a total cost of \(1\);
- if Pak Dengklek chose \(k = 3\) or \(k = 4\), then no roads need to be closed.

Therefore, the `minimum_closure_costs`

procedure should return \([10, 5, 1, 0, 0]\).

##### Example 2

Consider the following call:

`minimum_closure_costs(4, [0, 2, 0], [1, 0, 3], [5, 10, 5])`

This means there is a total of \(4\) junctions and \(3\) roads connecting the junction pairs \((0, 1)\), \((2, 0)\), and \((0, 3)\) with the closure costs \(5\), \(10\), and \(5\) respectively.

To obtain the minimum costs:

- if Pak Dengklek chose \(k = 0\), then all roads should be closed with a total cost of \(5 + 10 + 5 = 20\);
- if Pak Dengklek chose \(k = 1\), then road \(0\) and road \(2\) should be closed with a total cost of \(5 + 5 = 10\);
- if Pak Dengklek chose \(k = 2\), then either road \(0\) or road \(2\) should be closed with a total cost of \(5\);
- if Pak Dengklek chose \(k = 3\), then no roads need to be closed.

Therefore, the `minimum_closure_costs`

procedure should return \([20, 10, 5, 0]\).

#### Constraints

- \(2 \le N \le 100\,000\)
- \(0 \le U[i], V[i] \le N - 1\) (for all \(0 \le i \le N - 2\))
- It is possible to travel between any pair of junctions through the roads.
- \(1 \le W[i] \le 10^9\) (for all \(0 \le i \le N - 2\))

#### Subtasks

- (5 points) \(U[i] = 0\) (for all \(0 \le i \le N - 2\))
- (7 points) \(U[i] = i\), \(V[i] = i + 1\) (for all \(0 \le i \le N - 2\))
- (14 points) \(N \le 200\)
- (10 points) \(N \le 2000\)
- (17 points) \(W[i] = 1\) (for all \(0 \le i \le N - 2\))
- (25 points) \(W[i] \le 10\) (for all \(0 \le i \le N - 2\))
- (22 points) No additional constraints.

#### Sample Grader

The sample grader reads the input in the following format:

- line \(1\): \(N\)
- line \(2 + i\) (\(0 \le i \le N - 2\)): \(U[i] \; V[i] \; W[i]\)

The sample grader prints a single line containing the array returned by `minimum_closure_costs`

.

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